calculate the number of ions present in 0.025 g of sodium oxide
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Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.
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The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al=27 u.
Moles of Al
2
O
3
=
102
0.051
Number of molecules of Al
2
O
3
=
102
0.051
×6.023×10
23
=3×10
20
1 molecule of Al
2
O
3
contains 2 aluminium ions
so, 3×10
20
contains 6×10
20
aluminium ions
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