Question

Calculate the number of ions present in 10.6g of NA²CO³​

Answer 1

Answer:

1 mole of Na

2

CO

3

=106g

moles in 10.6g of Na

2

CO

3

=10.6/106=0.1 mole

106g contain atoms of oxygen =3×6.022×10

23

10.6 contain atoms =0.1×3×6.022×10

23

=1.8×10

23

atoms.