Question

Calculate the number of ions  present in 2.85g  of  MgCl2 .​

Answer 1

Answer:

1g of NaCl contains = (1/ 58.5) mole of NaCl molecules. 5.58g of NaCl contains = (1×× 5.58/58.5) mole

Explanation:

, there are four sodium ions in the unit cell of sodium chloride.