calculate the number of Ions present in 5.85 gram of sodium chloride
Answers
Answered by
3
Answer:
According to given data,
5.85 g of NaCl=
58.5
5.85
=0.1 moles of NaCl particle
Each NaCl particle contains 2 ions Na
+
and Cl
−
⇒ Total moles of ions =0.1×2 =0.2 moles
No. of ions =0.2×6.022×10
23
=1.2042×10
23
ions
Answered by
3
Answer:
According to given data,
5.85 g of NaCl=
58.5
5.85
=0.1 moles of NaCl particle
Each NaCl particle contains 2 ions Na
+
and Cl
−
⇒ Total moles of ions =0.1×2 =0.2 moles
No. of ions =0.2×6.022×10
23
=1.2042×10
23
ions
Explanation:
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