Chemistry, asked by Mayurkantmishra2854, 1 year ago

Calculate the number of ions present in 5.85g of nacl

Answers

Answered by Sikhachauhan
1

hope this will help you

Attachments:
Answered by Anonymous
5

\bf\huge\textbf{\underline{\underline{According\:to\:the\:Question}}}

\bf\huge{\implies 5.85g \:of\: Nacl = \dfrac{5.85}{58.5}\:=0.1\:moles}

Total moles of ions

= 0.1 × 2

= 0.2 moles

Now

Number of ions

\bf\huge{\implies 0.2\times 6.022\times 10^{23}}

\bf\huge{\implies 1.2042\times 10^{23}\:ions}


Anonymous: Mark as brainliest answer
Similar questions