Question

Calculate the number of iron atoms in a piece of iron weighing 2.8g

Answer 1

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No. of Iron atoms = N × moles ....( N = Avogadro number ....) ...

Moles = 5.6 / 56 = 0.1 ...

No. of atoms = 0.623 × 10^23 ....

Answer 2

Answer:

Number of iron atoms in a piece of iron weighing 2.8 g is $3.011\times 10^{22}$

Step-by-step explanation:

Given : A piece of iron weighing 2.8 g.

To find : Calculate the number of iron atoms in a piece of iron weighing 2.8 g?

Solution :

The formula to find the number of atoms is given by,

$N=\frac{W\times A_0}{w}$

Where, N is the number of atoms

W is the weight of the iron W=2.8 g.

w is teh molar mass of iron w=56 g.

$A_0=6.022\times 10^{23}$ is the Avogadro number

Substitute the value in the formula,

$N=\frac{2.8\times 6.022\times 10^{23}}{56}$

$N=\frac{1.68616\times 10^{24}}{56}$

$N=3.011\times 10^{22}$

Therefore, Number of iron atoms in a piece of iron weighing 2.8 g is $3.011\times 10^{22}$