Question

calculate the number of iron atoms present in 11.2g of iron​

Answer 1

Answer:

56 gm contains= 6.022×10^23

so 11.2 ........... =(6.022×10^23) /56 ×11.2

=1.2×10^23

Answer 2

No. of atom in Iron = $\bold {1.2044\times 10^2^3}$

Explanation:

We have to calculate number of iron atoms in 11.2 g of iron

Since,Mass number of iron = 55.845 u

No. of moles of iron in 11.2 g of iron = $\frac{11.2}{55.845}$

                                                           = 0.2

Now,No. of atom in Iron =  $No.\ of\ moles\ of\ iron\times Avogadro\ number$

                                        = $0.2\times 6.022\times 10^2^3$

                                        = $\bold {1.2044\times 10^2^3}$