Calculate the number of kj of heat necessary to raise the temperature of 60 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol-1 K-1.
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Answered by
17
Answer : ----
➡No. of moles of Al (m) = (60g)/(27 g mol-1)
= 2.22 mol
➡Molar heat capacity (C) = 24 J mol-1 K-1.
➡Rise in temperature (∆T) = 55 – 35 = 20°C = 20 K
➡Heat evolved (q) = C x m x T
▶ = (24 ) x (2.22) x (20 K)
= 1065.6 J
= 1.067 kj
➡No. of moles of Al (m) = (60g)/(27 g mol-1)
= 2.22 mol
➡Molar heat capacity (C) = 24 J mol-1 K-1.
➡Rise in temperature (∆T) = 55 – 35 = 20°C = 20 K
➡Heat evolved (q) = C x m x T
▶ = (24 ) x (2.22) x (20 K)
= 1065.6 J
= 1.067 kj
Answered by
29
given mass of Al = 60g
Molar mass of Al = 27 g/mol
so, mole = given mass/molar mass
= 60/27 = 20/9
A/C to question,
Molar heat capacity (C) = 24J/mol/K
Temperature change (∆T) = (55°C - 35°C) = 20°C or 20K
Heat {Q} = n.C.∆T
= 20/9 × 24 × 20 J
= 1066.67 J
= 1.0667 KJ
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