calculate the number of lithium ion present in 120 g of lithium oxide (given atomic mass of lithium =7u ,atomic mass of oxygen 16 I)please help
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lithium oxide is Li2O
molar mass of Li2O = 30 g
no of moles , n = 120/30
= 4
so,
4 = no. of molecules / 6.022*10²³
4*6.022*10²³=no of molecule
24.088*10²³ = no. of molecules
now each molecule contains 2 ions of lithium therefore in 24.088*10²³ number of lithium ions are
2*24.088*10²³=48.176*10²³ ions.... answer
molar mass of Li2O = 30 g
no of moles , n = 120/30
= 4
so,
4 = no. of molecules / 6.022*10²³
4*6.022*10²³=no of molecule
24.088*10²³ = no. of molecules
now each molecule contains 2 ions of lithium therefore in 24.088*10²³ number of lithium ions are
2*24.088*10²³=48.176*10²³ ions.... answer
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