Question

Calculate the number of milli-equivalents, gram eq. weight in grams and number of moles contained in 10 litres of 0.5 M Ba(OH)2 solution

Answer 1

Answer:

Explanation:

miili equivalent  = molarity*volume = 0.5*10000 = 5000

gram equivalent weight = mass/valency factor

moles = 0.5*10 = 5

mass = 855

valency factor = 2

equivalent mass = 855/2 = 427.5 gm

Answer 2

Answer:

Explanation:Normality of Ba(OH)2 solution = molarity ×acidity …(Eqn.6)

=0.5×2

1 N

m.e of the solution = normality × vol.in mL

=1×10000

=10000

Equivalent of the solution = m.e1000 …(Eqn.3)

=10001000

=10

Weight of Ba(OH)2 in solution = equivalent × eq.wt ....(Eqn.4)

=10×85.5

= 855 g

{equivalent wt. of Ba(OH)2=mol.wtacidity×1712=85.5}

Moles of Na(OH)2 solution = wt. in gramsmol .wt

=855171=5.00 moles .