calculate the number of mole of methane required to be burnt to produce 9gm of water.
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Answer:
ch4 +202 = co2 + 2h2o
16 g ch4 gives 36 g of water
by unitary method
9g of water will be produced by 4 g of methane
moles of methane req = mass/molar mass
moles = 0.25
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Explanation:
CH4+2O2=CO2 + 2H2O
16g CH4 gives 36g of H2O by unitary method.9g of H2O will be produced by 4g methane moles of methane req= mass/ molar mass moles =0.25
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