calculate the number of mole of water in 488gBaCl2.2H2O
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The molar mass (that is the mass of one mole) of BaCl2.2H2O is 244g. Each mole of this compound contains 2 moles of water. Thus
244 g of BaCl2.2H2O → 2 moles of water
1g of BaCl2.2H2O → (2 / 244) moles of water
488 g of BaCl2.2H2O → (2 X 488) / 244 moles of water
= 4 moles of water
So, 488g of BaCl2 contains 4 moles of water.
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244 g of BaCl2.2H2O → 2 moles of water
1g of BaCl2.2H2O → (2 / 244) moles of water
488 g of BaCl2.2H2O → (2 X 488) / 244 moles of water
= 4 moles of water
So, 488g of BaCl2 contains 4 moles of water.
Hope it's help you. Please mark me in brain list answer
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