Question

calculate the number of molecular of oxalic acid (H2C2O4.2H2O) in 100ml of 0.2N oxalic acid solution​

Answer 1

Answer:

Normality=molarity×basicity for acids/acidity for bases

Here N=0.02 & as oxalic acid is a dibasic acid so it will have a badicity of 2.

M=0.02÷2=0.01

Molarity=no of moles × volume(lit)

M=0.01×0.1=0.001moles

As 1 mole= 6.603×10*23=6.6×10*23×0.001= 6.6×10*20.