Question

Calculate the number of molecule in 50 gram of CaCo3.calculate mass 0.5moles of nitrogen gas

Answer 1

Answer:

CaCo3=40+12+16×3=40+12+48=100

n= m/M

n=50/100=.5mole

n=N/No

N=n×No

N=.5×6.022×10^23

N=3.011×10^23

N gas= N2 = 28

n=m/M

m=n×M

m=.5×28

m=14