Calculate the number of molecules and atoms present in 11.2l of o2 at ntp
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1 mole of any substance occupies 22.4 litre of volume at STP
22.4 l = 1 mole = avagadro's number of particles
11.2 l of oxygen= 1/2 Mole of oxygen= N•/2 number of oxygen molecules= 6.022 * 10^22 = 3.011 * 10^22 molecules
22.4 l = 1 mole = avagadro's number of particles
11.2 l of oxygen= 1/2 Mole of oxygen= N•/2 number of oxygen molecules= 6.022 * 10^22 = 3.011 * 10^22 molecules
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