Question

calculate the number of molecules and number of atoms present in 5.06 l of ozone (O3) at ntp​

Answer 1

Answer:

Explanation:

1 mole contains 22.4 liter of Ozone gas

so, 5.6 contains,

(5.6)/(22.4) = 0.25 mole

1 mole = 6.023×10²³ molecules

0.25 mole = 0.25×6.023×10²³ molecules

                =1.506×10²³ molecules.

Answer 2

Explanation:

Answer in the figure

Hope this will help you