calculate the number of molecules and number of atoms present in 11.2 litres of oxygen at ntp
Answers
Answered by
5
1 mole of any substance occupies 22.4 litre of volume at STP
22.4 l = 1 mole = avagadro's number of particles
11.2 l of oxygen
= 1/2 Mole of oxygen
= N•/2 number of oxygen molecules
= 6.022 * 10^22
= 3.011 * 10^22 molecules
22.4 l = 1 mole = avagadro's number of particles
11.2 l of oxygen
= 1/2 Mole of oxygen
= N•/2 number of oxygen molecules
= 6.022 * 10^22
= 3.011 * 10^22 molecules
Similar questions