calculate the number of molecules and volume of carbon dioxide released when 150 grams of calcium
Answers
Answered by
0
Answer:
CaCO
3
+2HCl→CaCl
2
+H
2
O+CO
2
↑
1 mole of calcium carbonate gives 1 mole of CO
2
Molar mass of calcium carbonate =40+12+3(16)=100 g/mol.
150 grams of calcium carbonate corresponds to
100 g/mol
150 g
=1.50 moles of calcium carbonate.
They will give 1.50 moles of CO
2
.
The molar mass of CO
2
is 44 g/mol.
Mass of CO
2
=1.5 mol×44g/mol=66 mol
Explanation:
Similar questions