Question

calculate the number of molecules in 1 cm cube of an ideal gas at ntp

Answer 1

1 mol of any gas at NTP occupies volume of 22400 cm³

Volume of 6.022 × 10²³ molecules of gas = 22400 cm³

Number of molecules in 1 cm³ of Volume
= 1 cm³ × 6.022 × 10²³ molecules / (22400 cm³)
= 2.7 × 10¹⁹ molecules

Answer 2

1 mol of any gas at NTP has volume of 22400 cm³

thus Volume of 6.022 × 10²³ molecules of gas = 22400 cm³

thus Number of molecules in 1 cm³ of Volume

= 1 cm³ × 6.022 × 10²³ molecules / (22400 cm³)

= 2.7 × 10¹⁹ molecules