Calculate the number of molecules in 10 gram of ethyl alcohol
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0
Answer:
Molar mass of C
2
H
5
OH = 46 g
No. of molecules present in 1 mole of C
2
H
5
OH = 6.022×10
23
No. of moles of C
2
H
5
OH =
46
46
=1
So, the no. of molecules of C
2
H
5
OH present in 1 mole of C
2
H
5
OH = 1×6.022×10
23
=6.022×10
23
Answered by
0
Explanation:
- n.o of molecules in 10 g of ethyl alcohol=10×46×6.022×10^23
- =27.7× 10 ki power 26
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