Question

calculate the number of molecules in 12g of KClO3.​

Answer 1

Answer:Suppose we were asked to figure out the mole fraction of cadmium nitrate in a 12% (wt-wt) aqueous solution. 12% (wt-wt) tells us that there is 12% in weight of the solute in 100 g of the solution. For a 12% (wt-wt) aqueous Cd(NO_3  

3

start subscript, 3, end subscript)_2  

2

start subscript, 2, end subscript solution, let’s suppose we have 100 grams of the substance. There would be 12 g of the solute and 88 g of water.

\begin{aligned} Cd(NO_3)_2: &112 + (14 \times 2) + (16 \times 6) \\\\ =& 112 + 28 + 96 \\\\ =& 236 g/mol \end{aligned}  

Cd(NO  3  )  2 : = =

​112+(14×2)+(16×6)

112+28+96

236g/mol

​  

Explanation:

Answer 2

122.5 g of KClO3 = 1 mole of Kclo3 =

$6.022 { \times 10 }^{ 23} molecules$

number of molecules in 12g of KClO3. will be

$6.022 \times 10 {}^{23} \div 122.5 \times 12 = 0.59 \times 10 {}^{23 } = 5.9 \times 10 {}^{22}molecules$