Calculate the number of molecules in 22 gram of Methane
Answers
Answered by
26
given ,
mass (m) =22
molecular mass of methane (M) = 1×atomic mass of C + 4× atomic mass of H
=1×12+4×1
=16
number of moles= m/M
=22/16
=1.375
number of molecules=n× avogadro's number
= 1.375×6.022×10^23
=8.20825×10^23
mass (m) =22
molecular mass of methane (M) = 1×atomic mass of C + 4× atomic mass of H
=1×12+4×1
=16
number of moles= m/M
=22/16
=1.375
number of molecules=n× avogadro's number
= 1.375×6.022×10^23
=8.20825×10^23
Answered by
9
Methane's chemical formula is CH4
So its molecular mass = molecular mass of C + molecular mass of H × 4
= 12 + 1 × 4
= 12 + 4
= 16 u
So molar mass would be 16 g
Now given mass = 22g
Molar mass = 16 g
Mole = given mass/ molar mass
= 22/16
= 11/8 mol
Number of molecules = mol × Avogadro number
= 11/8 × 6.022 × 10²³
= 8.28025 × 10²³ molecules.
Or,
8.28 × 10²³ molecules (approx)
So its molecular mass = molecular mass of C + molecular mass of H × 4
= 12 + 1 × 4
= 12 + 4
= 16 u
So molar mass would be 16 g
Now given mass = 22g
Molar mass = 16 g
Mole = given mass/ molar mass
= 22/16
= 11/8 mol
Number of molecules = mol × Avogadro number
= 11/8 × 6.022 × 10²³
= 8.28025 × 10²³ molecules.
Or,
8.28 × 10²³ molecules (approx)
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