Calculate the number of molecules in 270 g of aluminum
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13gof Al has 6*10^23 molecules one g of Al has( 6*10^23)/13 and 270g of Al will have ( 6*10^23)/13*270
PurnimaMonga:
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Number of moles*avagadro number
I.e; 270/27*6.022*10^23
I.e; 270/27*6.022*10^23
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