Question

Calculate the number of molecules in 50 g of CaCO 3 . (AM of Ca = 40 u, C = 12 u and O = 16 u)
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Answer 1

Answer:3.011×1023

Explanation:Given mass=50g

Molar mass of Caco3 is =40+12+3×16=100

Number of moles of Caco3 will be 50/100=0.5

1 mol of Caco3 contains 6.022 ×1023 molecules

Hence 0.5 mol of Caco3 molecules will contain

0.5×6.022 ×10 23 which gives 3.011 ×10 23

Answer 2

Answer:

Half of avogadro number of molecules [ 3.011 x 10^23 ]

Explanation:

Total atomic mass of the compound : 40 + 12 + (16 x 3) = 100 amu

No. of moles = (Given mass) / (Total atomic mass of the compound)

Therefore no. of moles in CaCO3 = 50 / 100

                                                        = 1 / 2

No. of molecules = (No. of moles) x (Avogadro no.)

                            = (1 / 2) x (6.022 x 10^23) molecules

                            = 3.011 x 10^23 molecules