Question

calculate the number of molecules in 56g of nitrogen gas

Answer 1

1 mole of Nitrogen gas= 6.022×10^23 molecules=28g og Nitrogen gas
molecules in 28g=6.022×10^23
molecules in 1 g=6.022×10^23/28
molecules in 56g= 6.022×10^23/28×56
=6.022×10^23×2
=12.044×10^23
So no. of molecules in 56g of Nitrogen gas is 12.044×10^23

Answer 2

56g of nitrogen gas has $12.046×10^{23}$ number of molecules.

Given: 56g of nitrogen gas.

To find: We have to find the number of molecules.

Solution:

The molecular mass of nitrogen gas is 28gram.

28 grams of nitrogen gas has 1 mole.

56 grams of nitrogen gas has 56/28=2 moles.

1 mole of nitrogen gas will occupy $6.023×10^{23}$ number of molecules.

2 mole of nitrogen gas will occupy $2×6.023×10^{23}=12.046×10^{23}$ number of molecules.

56g of nitrogen gas has $12.046×10^{23}$ number of molecules.