Calculate the number of molecules in 8.5 gm Ammonia (atomic mass of H=1u,N=14u)
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Hi.
Here is your answer----
Mass of Ammonia (NH3) = 8.5 grams.
Molecular mass of Ammonia(NH3) = 17 grams
Using formula,
Number of molecules = (Mass/molecular mass) x Avogadro's number
= (8.5/17) x 6.022 x 10^23
= 3.011 x 10^23
Thus, number of molecules in 8.5 grams of Ammonia is 3.011 x 10^23
Hope it helps.
Have a nice day.
Here is your answer----
Mass of Ammonia (NH3) = 8.5 grams.
Molecular mass of Ammonia(NH3) = 17 grams
Using formula,
Number of molecules = (Mass/molecular mass) x Avogadro's number
= (8.5/17) x 6.022 x 10^23
= 3.011 x 10^23
Thus, number of molecules in 8.5 grams of Ammonia is 3.011 x 10^23
Hope it helps.
Have a nice day.
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