Question

Calculate the number of molecules of 0.5g of CaCO3. (Avogadro's number=6.02×10^²³ Atoms per molecules​

Answer 1

n/N=m/M

n=no. of moles

N=Avogadro's number=6.02×10^²³

m=given mass=0.5g

M=molar mass=100(CaCO3)

⇒n=0.5/100×6.02×10^²³

n=3.01×10^22

hope it helps