Question

calculate the number of molecules of a SO2 gas when libarated of consuming of 3 moles of Oxygen gas at STP​

Answer 1

$18.07\times 10^{23}$ molecules  of a $SO_2$ gas when libarated of consuming of 3 moles of Oxygen gas at STP​

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass, occupies 22.4 L of volume at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

$S+O_2\rightarrow SO_2$

According to stoichiometry:

1 mole of oxygen liberate = 1 mole of sulphur dioxide

3 moles of oxygen will liberate = $\frac{1}{1}\times 3=3moles$ of sulphur dioxide

1 mole of sulphur dioxide =  $6.023\times 10^{23}$ molecul;es

3 moles of sulphur dioxide =  $\frac{6.023\times 10^{23}}{1}\times 3=18.07\times 10^{23}$ molecules

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