Question

calculate the number of molecules of carbon dioxide present in 300 ml of gas at 273 Kelvin and 2.5 atm pressure?
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Answer 1

Answer:

Explanation:

From the given question,

Pressure (p)=2.5atm

Temperature(T)=273k

Volume(V)=300ml

=300/1000

=0.3l

We know that,

PV=nRT

Where,

n=no of moles

R=0.082

So,

2.5×0.3=n×0.082×273

n=2.5×0.3/0.082×273

n=0.03moles

Now,

We know that,

No of molecules (N)=no of moles(n)×6×10^23

N=0.03×6×10^23

=3×6×10^21

--------== N=1.8×10^22 molecules

Answer 2

Answer:

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