calculate the number of molecules of CO2, Hydrogen and oxygen atom in 360 gm glucose
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Molecular formula =C6H1206 Molar mass = 6 x 12 + 12 x 1+ 16 x 6 = 180gmol 1 18 Moles in 18g of sample= 180 0.1mole So,moles of carbon present in sample= 0.1 x 6 = 0.6 Moles of hydrogen= 0.1 x 12 = 1.2 Moles of oxygen= 6 x 0.1 = 0.6 No. of atoms present in carbon= 0.6 x 6.022 x 1023 = 3.6 x 1023 %3D No. of atoms present in hydrogen= 1.2 x 6.022 x 1023 = 7.2 x 1023 No. of atoms present in oxygen= 0.6 x 6.022 x 1023 = 3.6 x 1023 %3D
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