Question

calculate the number of molecules of methane in 0.50 m^3 of the gas at a pressure of 2.0× 10^2 kPa and a temperature of exactly 300K​

Answer 1

p = 2× 10^2 k pa = 2× 10^2. × 10^3 pa =2×10^5 paT = 300 k.V = o.50 dm^3.R = 0.082057 atm 2 mol^-1 k -1. = 8.3145 mol^-1 m^-1. so by using ideal gas equation. we have PV= nRT 2×10^5 pa × 0.50 dm^3 = n × 8.3145 mol^-1k^-1×300 k. n = 2×10^5 pa × 0.50 dm^3/(8.3145mol^-1k^-1×300 k.. n = 10^5 pa dm^3/2494.35 mol. n = 2.414 × 10^-1 ×10 ^26. n = 2.414 x 10 25.......... HOPE IT WILL HELP YOU.PLEASE MAKE IT AS A BRAIN LIST ANSWERS