Question

calculate the number of molecules of N2 gas required to produce 3.4 grms of NH3 at stp in reaction with excess of hydrogen gas​

Answer 1

Answer:DDR DINESH

Explanation:

Answer 2

Answer:

0.1 mol of N2 molecule

Explanation:

N2+3H2=2NH3

SO excess hydrogen

molar mass of NH3=17g/mol

1mol N2=====>2NH3

3.4g NH3=3.4/17=0.2mol ammonia

1N2====>2NH3

xN2====>0.2NH3

X=0.2/2=0.1mol