Calculate the number of molecules of NH3 gas present in 448 ml of it at STP
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Answer:-
Oxygen = 448 ml
moles produced =O2
22400 =448
=0.02moles
→2KCl+3O 2
POAC in Oxygen Atoms
Oxygen in KClO3 oxygen in O2
KClO3) = 3 moles of O2
(=3×0.022× 122.5x)
=0.06
x=0.03×122.5
x=3.675g
Answer=3.675g
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