Question

calculate the number of molecules of O2 liberated on heating 24.5 g of kclo3 at stp​

Answer 1

Answer:

The chemical equation for decomposition of KClO3 can be written as:

2KClO3→2KCl+3O2

245 g of KClO3 gives 67.2 L of O2 at STP.

12.25 g of KClO3 gives 24567.2×12.25 =3.36 L.