Question

Calculate the number of molecules of oxygen gas that occupies a volume of 224 ml at 273 K and 3 atm pressure.​

Answer 1

Answer:

Temperature of the Gas(T) = 273 K. and n = number of moles. ⇒ n = 0.02 moles. Thus, the number of the molecules of the Oxygen gas is 0.121 × 10²³ molecules.

Answer 2

Explanation:

Volume of the gas =224ml

=0.224litre

Temperature of the gas =273 K

Pressure of the gas =3 atm

Now,

PV=nRT

Where,R = Gas Constant =0.082 Latm mol^-1k-1

●2×0.224=n×0.082×273

=>0.448=22.386×n

=>n=0.448/22.386

=>n=0.22 moles

Now

No.of molecules = no .of moles×6.022×10^23

=>0.02×6.022×10^23

=>0.121×10^23

Thus, The no .of the molecules of the oxygen gas is 121.×10^23...

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