Question

calculate the number of molecules of phosphorous (P4) present in 248g of solid phosphorous.(given atomic mass of phosphorous =31.0u no. = 6.022x1023per mole)

Answer 1

248g of solid phosphorous contains $4.8\times10^{23}$ molecules of phosphorous.

Given:

Weight of phosphorous = 248g

Atomic mass of phosphorous = 31

1 mole of phosphorous = $6.022\times10^{23}$ molecules.

To find:

Number of molecules of phosphorous (P4) present in 248g of solid phosphorous = ?

Formula to be used:

• Number of moles = $\frac{Given mass}{Atomic mass}$
• Number of molecules = No. of moles × Avogadro's number

Calculation:

Calculation of number of moles:

Number of moles = $\frac{Given mass}{Atomic mass}$

Number of moles = $\frac{248}{31} = 8$

Number of moles = 8

Calculation of number of molecules:

Number of molecules = No. of moles × Avogadro's number

Number of molecules = 8 × $6.022\times10^{23}$

Number of molecules = $48\times 10^{23}$

Number of molecules = $4.8\times10^{24}$

Conclusion:

Thus 248g of solid phosphorous contains  $4.8\times10^{24}$ molecules.

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