Question

calculate the number of molecules of phosphorus present in 248 gram of solid phosphorus​

Answer 1

Answer:

hi!!!!!

answer248 gm of solid phosphorus = 248/31 = 8 moles.

1 mole of phosphorus = 6.022x1023 molecules.

8 mole of phosphorus = 8 x 6.022x1023

= 48.176 x 1023 molecules.

hope it helps...

Explanation:

Answer 2

The number of molecules of solid phosphorus present are $1.2044\times 10^{24}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $P_4$ = 248 g

Molar mass of $P_4$ = 124 g/mol

Putting values in above equation, we get:

$\text{Moles of }P_4=\frac{248g}{124g/mol}=2mol$

According to mole concept:

1 mole of compound contains $6.022\times 10^{23}$ number of molecules

So, 2 moles of $P_4$ will contain = $(2\times 6.022\times 10^{23}=1.2044\times 10^{24}$ number of molecules

Learn more about mole concept:

https://brainly.in/question/13534028

https://brainly.in/question/6384517

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