Question

Calculate the number of molecules of SO2 present in 44g of it. (S-32u, O- 16u)

Answer 1

Answer:

The number of molecules of $SO_2$ present in 44 g of$SO_2$ is $4.14 \times 10^{23}.$

Explanation:

The molar mass of  $SO_2$ is 32 + 16 + 16 = 64g/mol.

The number of moles of $SO_2$ present in 44 g of $SO_2$ is = 44/64 = 0.6875 mol.

1 mole of any substance contains Avogadro's number of molecules which is $6.022 \times 10^{23}$.

Thus, the number of molecules of $SO_2$ present in 44 g of$SO_2$ is

$= 0.6875 \times 6.022 \times 10^{23}\\= 4.14 \times 10^{23}$

Hence, the number of molecules of $SO_2$ present in 44 g of$SO_2$ is $4.14 \times 10^{23}.$