calculate
the number of molecules of sulphur is at present in 16 gram of solid Sulphur
Answers
Answered by
5
molecular mass of sulphur s8= 32 (which is atomic mass of s ) x 8
= 256 u
so, one mole of s8 molecule is 256 g and 1 mole of s8 molecule contains 6.022 x 10 exponent 23.
so, no of moles present in 16 g os solid sulphur=
16/256 =0.0625 moles
so, no of molecules present in 16g of s8 = 6.022 x 10 exponent 23 x 0.0625
=0.376375x 10 exponent 23
= 256 u
so, one mole of s8 molecule is 256 g and 1 mole of s8 molecule contains 6.022 x 10 exponent 23.
so, no of moles present in 16 g os solid sulphur=
16/256 =0.0625 moles
so, no of molecules present in 16g of s8 = 6.022 x 10 exponent 23 x 0.0625
=0.376375x 10 exponent 23
Answered by
4
☺ Hello mate__ ❤
◾◾here is your answer.
1 mole of solid sulphur (S8)
= 8 × 32g
= 256g
i.e., 256g of solid sulphur contains
= 6.022 × 10^23 molecules
Then, 16g of solid sulpur contains
(6.022×10^23 /256 )16 molecules
= 3.76 × 10^22 molecules (approx)
____________________________
I hope, this will help you.☺
Thank you______❤
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