calculate the number of molecules of sulphur present in 16 grams of solid sulphur
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Answered by
17
Atomic mass of S = 32g
Molecular mass of S8 = 8 x 32 = 256 g
Given mass of S8 = 16 g
Since 1 mole of S8 having mass 256 g contains 6.022 x 10∧23 molecules of Sulphur
Therefore 16 g of S8 will contain 6.022 x 10∧23 ÷ 256 x 16
= 3.76 x 10∧22 molecules
Molecular mass of S8 = 8 x 32 = 256 g
Given mass of S8 = 16 g
Since 1 mole of S8 having mass 256 g contains 6.022 x 10∧23 molecules of Sulphur
Therefore 16 g of S8 will contain 6.022 x 10∧23 ÷ 256 x 16
= 3.76 x 10∧22 molecules
Answered by
6
☺ Hello mate__ ❤
◾◾here is your answer.
1 mole of solid sulphur (S8)
= 8 × 32g
= 256g
i.e., 256g of solid sulphur contains
= 6.022 × 10^23 molecules
Then, 16g of solid sulpur contains
(6.022×10^23 /256 )16 molecules
= 3.76 × 10^22 molecules (approx)
____________________________
I hope, this will help you.☺
Thank you______❤
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