Question

calculate the number of molecules of sulphur s8 present in 16g of solid sulphur​

Answer 1

❥ANSWER

The molecular mass of s8 sulphur is 32×8=256g

256g sulphur contain avogadro number of molecules.

16g contains 6.023×10²³×(16/256) molecules

= 3.764375×10²² molecules

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Answer 2

Final answer: The number of molecules of Sulphur $S_{8}$ present in 16g of solid Sulphur = $3.764\times10^{22}$

Given that: We are given $16$ $g$ of solid Sulphur​.

To find: We have to find the number of molecules of Sulphur $S_{8}$ present in $16$ $g$ of solid Sulphur​.

Explanation:

First we have to calculate the number of moles of Sulphur $S_{8}$ present in $16$ $g$ of solid Sulphur.

• $Number of moles = \frac{Given mass(g)}{Molecular mass(\frac{g}{mol})}$

• $Number of moles of S8 = \frac{Given mass of S_{8} (g)}{Molecular mass of S_{8}(\frac{g}{mol})}$

Given mass of $S_{8}$ =  $16$ $g$

Molecular mass of $S_{8}$ = $32\times8 = 256$ $\frac{g}{mol}$

• Number of moles of $S_{8}$ $\\=\frac{16g}{256 (\frac{g}{mol})}=0.625 mol$

Now we have to calculate the number of molecules of Sulphur $S_{8}$ present in $16$ $g$ of solid Sulphur.

• We know that one mole of any substance contains Avogadro's number ($6.023\times 10^{23}$) molecules.

• Thus, “$n$” number of mole contains $n\times(6.023\times10^{23})$ molecule.

• The number of molecules in $0.625$ $mol$ of $S_{8}$ = $0.0625\times(6.023\times10^{23})$

                                                                                  = $3.7637\times10^{22}$

                                                                                  = $3.764\times10^{22}$

Hence, the number of molecules of Sulphur $S_{8}$ present in $16$ $g$ of solid Sulphur = $3.764\times10^{22}$

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