Question

Calculate the number of molecules of sulphur (S8) present in 16 g of solid sulphur.​

Answer 1

Answer:

This means 256 g of solid sulphur contains = 6.022 x 1023 molecules. Therefore, 16 g of S8 contains 3.76 x 1022 molecules.

Hope it helps

Answer 2

$\huge{\underline{\underline{\huge{\bold{AnsweR \: :-}}}}}$

We have to find the number of molecules present in 16g of solid sulphur.

$\sf\:The\: molecular\: mass\: of \:the \:sulphur\: molecule\: is \:32 × 8 = 256\: u.$

$\sf\:1\: mole\: of \:sulphur \:molecules\: is \:equal \:to \:256 \:grams.$

$\sf\:This\: means\: 256\: g\: of\: solid \:sulphur\: contains\: = 6.022 \:x\: 10²³\: molecules.$

$\sf\:Then,\: 16\: g \:of \:solid \:sulphur \:contains \:=6.022\: x \:10²³ / 256 = 16 \:molecules$

=$\sf\: 3.76375\: x \:10²² \:molecules$

Therefore, 16 g of S8 contains 3.76 x 10²² molecules.