Question

Calculate the number of molecules of sulphur (S8) present in 128 g of solid sulphur.
plzzzzzzzzanswer fast.........

Answer 1

Molar mass of sulphur molecule=8×32=256u
Number of moles of sulphur=Given mass/Molar mass
=m/M=128/256=1/2
Number of moles of sulphur=given number of particles/Avagadro number
or n=N/No
or 1/2=N/6.022×10^2 3
or 2×N=6.022×10^23
or N=6.022×10^23/2=3.011×10^23

Answer 2

$<b>$☺ Hello mate__ ❤

◾◾here is your answer.

1 mole of solid sulphur (S8)

= 8 × 32g

= 256g

i.e., 256g of solid sulphur contains

= 6.022 × 10^23 molecules

Then, 128g of solid sulpur contains

(6.022×10^23 /256 )128 molecules

= 3.o11 × 10^23 molecules (approx)

____________________________

I hope, this will help you.☺

Thank you______❤

✿┅═══❁✿ Be Brainly✿❁═══┅✿