Calculate the number of molecules present in 1.12 x 10
cc of a gas at STP.
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Explanation:
At S.T.P, the volume of one mole of a gas is 22.4 L
1 L = 1000cc
therefore,
1.12 X 10 X 1000 L volume is present at STP. Using unitary method ,
22.4 L for one mole,
11200 L for X moles
therefore X= 500 moles
The number of molecules can then be found out easily by using n X Avogadro's number
we get,
500 X 6.022X 10^23
= 30.110 X 10 ^23 molecules
hope you understand....
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