Question

calculate the number of molecules present in 11.5 dm^3 of N2 at STP .....please give me the accurate answer​ in mathematicall form​

Answer 1

3.089 × 10^23

Explanation:

By formula it is known that at STP condition the no of moles is equal to volume of gas in ltre divided by 22.4.Hence since the volume of gas is 11.5 then by putting the value in formula ( no of moles = Volume of gas in litre /22.4) we get 0.513 moles. Now by using another relation

(no of moles =given particles / 6.022 ×10^23) no of molecules will be 3.089×10^23