calculate the number of molecules present in 224 L oxygen gas at stp?
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Answer:
Correct option is
D
12×10
23
Number of moles in 22.4 L of O
2
at STP =22.4/22.4=1 mole
Number of atoms present in 1 mole of oxygen=6×10
23
so total no. of oxygen atoms=2×6×10
23
=12×10
23
atoms
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Answer:
10 × N0 moles of oxygen gas
N0 ( avagadro number )
Explanation:
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