calculate the number of molecules present in 27 g of H2O and 16 g of S8
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The molecules formula of sulphur is given to be S8 ( it Contains 8 atoms of sulphur ). So , the molecular mass of sulphur molecule is 32 × 8 = 256 u. This means that 1 mole of sulphur molecules is equal to 256 grams.
Now, 256 g of sulphur = 1 mole of sulphur molecules
, 16 g of sulphur = 1/ 256 × 16 mole of sulphur molecules
= 0.0625 mole of sulphur molecules
Also, 1 mole of sulphur molecules = 6.023 × 10²³ molecules
So, 0.0625 mole of sulphur molecules = 6.025 × 10²³ × 0.0625 molecules
= 3.76 × 10²² molecules
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Now, 256 g of sulphur = 1 mole of sulphur molecules
, 16 g of sulphur = 1/ 256 × 16 mole of sulphur molecules
= 0.0625 mole of sulphur molecules
Also, 1 mole of sulphur molecules = 6.023 × 10²³ molecules
So, 0.0625 mole of sulphur molecules = 6.025 × 10²³ × 0.0625 molecules
= 3.76 × 10²² molecules
PLEASE MARK MY ANSWER AS A BRAINLIEST.
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