Question

calculate the number of molecules present in 350cm3 of NH3 gas at 273k and 2 atmosphere pressure

Answer 1

350cc =0.35L
T=273K
R=8.3244
use PV=nRT
Substituting the value and calculating for the value of n
we get n = 3.08 x 10-4.
I hope it helps u.

Answer 2

The number of molecules present in $350\ \mathrm{cm}^{3} \text { of } \mathrm{NH}_{3}$ gas at 273k and 2 atmosphere is $\bold{3.08 \times 10^{-4}}$.

Given:

Temperature = 273 K

$350\ \mathrm{cm}^{3} \text { of } \mathrm{NH}_{3}=0.35 \mathrm{L}$

R (ideal gas constant) = 8.3244

Formula = PV = nRT

Calculating the value of $\bold{n=3.08 \times 10^{-4}}$

Molecules are defined as the smallest particle in a compound or element which is held together with the chemical bonds. These bonds are formed as a result of element sharing or bonding. Molecules are eminent part of any chemical compounds or chemical elements.