Calculate the number of molecules present in 42 g of magnesium
carbonate.
Answers
Answer:
23 molecules.
Explanation:
Molecular mass of NaHCO
3
= (Atomic mass of Na)+(Atomic mass of H) + (Atomic mass of C) +3× (Atomic mass of O)
=23+1+12+3(16)
=84
Number of moles of NaHCO
3
= Molecular mass
Mass of NaHCO
3
in grams
84
42
=0.5 mole
According to Avogadro's number, number of molecules of NaHCO
3
= mole × Avogadro number
=0.5×6.022×10
23
=3.011×10
23 molecules
42 grams sodium hydrogen carbonate (NaHCO 3 ) contains 3.011×10
23molecules.
Answer:
Molecular mass of NaHCO
3
= (Atomic mass of Na)+(Atomic mass of H) + (Atomic mass of C) +3× (Atomic mass of O)
=23+1+12+3(16)
=84
Number of moles of NaHCO
3
=
Molecular mass
Mass of NaHCO
3
in grams
=
84
42
=0.5 mole
According to Avogadro's number, number of molecules of NaHCO
3
= mole × Avogadro number
=0.5×6.022×10
23
=3.011×10
23
molecules
42 grams sodium hydrogen carbonate (NaHCO
3
) contains 3.011×10
23
molecules.