Question

calculate the number of molecules present in 6.3gms of HNO3

Answer 1

Answer:

0.6023*10^23(0.1*Avagadro no)

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Answer 2

Explanation:

Therefore, In 6.3 g of nitric acid, 6.022 X 10 22 atoms of hydrogen, 6.022 X 10 22 atoms of nitrogen and 18.06 X 10 22 atoms of oxygen are present.